Question

A bus left Raipur at 6 a.m. and stopped in between for 30 minutes. It reached
Nagpur at 6:30 p.m. on the same day. If the total distance covered by the bus is
300 km, find the speed of the bus.​

Answer 1

Answer:

$\huge{\fbox{\fbox{\bigstar{\mathfrak{\pink{Answer}}}}}}$

Step-by-step explanation:

$\star\underline\mathcal\purple{bus \: starts \: from \: raipur \: at} = = > \underline\green{6 \: a.m} \\ \star\underline\mathcal\purple{bus \: reach \:at \: raipur} = = > \underline\green{6.30pm} \\ \star\underline\mathcal\purple{bus \: stopped \: in \: between \: for} = = > \underline\green{30 \: minutes} \\ \\ \\ \star\underline\mathcal\purple{so \: net \: time} = = > \underline\green{actual \: time - stopped \: time} \\ = = = = = = = = = > \underline\green{12.30 \: hours - 30 \: minutes} \\ = = = = = = = = = > \underline\green{ 12 \: hours} \\ \\ \\ {\fbox{\fbox{{\mathfrak{\red{speed = \frac{distance}{time} }}}}}} \\ \\ \\ = = > \underline\mathcal\purple{distance } =\underline\green{300 \: km} \\ = = > \underline\mathcal\purple{time} =\underline\green{12 \: hours}\ \\ = = > \underline\pink{speed = \frac{300}{12} } = \underline\green{25km \: hour {}^{ - 1} }$

_______________________________

HOPE IT HELPED ✌️❤️❤️

_______________________________

^_^

Answer 2

$\huge{\underline{\underline{\red{♡Solution→}}}}$

→

$\bold{\huge{\underline{\underline{\rm{ Given :}}}}}$

Bus left Raipur at 6:00 A.M.

Bus Reached Nagpur at 6:30 Pm

Bus stopped in between for 30 Minutes.

The total distance covered by bus = 300 Km.

$\bold{\huge{\underline{\underline{\rm{ To\:Find :}}}}}$

The speed of bus .

__________________________

$\</strong><strong>p</strong><strong>u</strong><strong>r</strong><strong>p</strong><strong>l</strong><strong>e</strong><strong>{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

Bus start at 6: 00 Am and reached at 6:30 Pm and stopped in between for 30 Minutes-

So , net time = 12 Hr 30 minutes - 30 minutes

Net time = 12 Hr

We know that →

• $distance \: = speed \times time$

So,

$speed = distance \div time$

$speed \: = \frac{300}{12}$

$</strong><strong>\</strong><strong>b</strong><strong>o</strong><strong>x</strong><strong>e</strong><strong>d</strong><strong>{</strong><strong>speed</strong><strong> \: = 25 \: km \: </strong><strong>/</strong><strong> \: hr</strong><strong>}</strong><strong>$

__________________________

───── ❝ TheEnforceR ❞ ─────

Mark as Brainliest !! ✨✨