Question

A bus left Rourkela at 6 pm and stopped in between for one hour . It reached Jamshedpur at 7 am on the next day. If the total distance covered by the bus is 480 km . find the speed of the bus
please help me​

Answer 1

Answer:

40 kmph

Step-by-step explanation:

Speed = distance / time

distance = 480 km

time = 12 hrs ( time between 6 pm and 7 am minus 1 because it stopped for one hour)

speed =480/12

= 40 kmph

Therefore speed of the bus is 40kmph.

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Hope this helps!

Answer 2

Answer:

40 kmph

Step-by-step explanation:

left Rourkela at 6pm and reach jamshedpur at 7am.

i. e. it took 13 hours

Stoppage = 1 hour

Actual Travel time = 13-1 = 12 hour

Distance = speed * time

Distance = 480 km

Time = 12 hour

$speed = \frac{480}{12} = 40 \: kmph$

Speed of the bus = 40 kmph