A bus moves at uniform speed v1 for sometime and then with a uniform speed v2. The distance-time table is given below. Flot the distance-time graph and answer the following questions? Time(min.)-0,20,40,60,80,100,120.
Distance(km)-0,20,40,65,95,125,155.(1)Find the value of v1 and v2.
(2)What is the distance covered in the first hour.
(3)What is the distance covered in the second hour.
(4)When did the bus change its speed.
(5)What is the average speed for the complete journey.
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Answer:
a.) v¹=40-0/40-0 = 1km/min =1×60km/h =60km/h, v²=95-65/80-65 =2km/min =2×60 km/h = 120 km/h
b.)40 minutes(according to the graph
c.)For the first hour =60min
=65 km (according to the graph)
d.)For the second =2h=120min
=155-65
=90km
e.)155/120
=1.30 km/h
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