Question

A bus moves away from rest at a bus stop with acceleration of 1m/s^2.As the bus starts to move a man who is 4m behind the stop with a constant speed after the bus. If he just manage to catch the bus find his speed?

Answer 1

Answer:

Let man will catch the bus after time t.Since the distance from man position is same for both at time t

⇒ Distance covered by bus = Distance covered by man -48

⇒

2

1

at

2

=vt−48

⇒

2

1

(1)t

2

=10t−48

⇒t

2

−20t+96=0

⇒(t−12)(t−8)=0

⇒t=8s (minimum value) or t=12s

So,at t=8s,the man will catch the bus

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