Question

A bus moves from stop a to stop b' with a speed of 40 km/hr and then from stop b' to stop a with a speed of 50 km/hr. Its average speed is

Answer 1

such type of question when the distance travelled is same on both the side but the velocity of the speed with which the distance is covered is different we use a short simple trick or a formula to find the average speed which is:

average speed= 2v'v"/v'+v"

here v' is the speed in the first part of the journey.

v" is the speed in the second part of the journey.

show the average speed in this case becomes to be:

(2×40×50)/(40+50)

so av. speed is 400/9 = 44.4 km/hr.

Answer 2

Answer: The correct answer is 44.4km/hr