Question

A bus moves from stop A to stop B with a speed of 40 km/hr and then from stop B to stop A with a speed of 50 km/hr. its average speed is ​

Answer 1

Answer:

45 km /h

Explanation:

average speed = total distance traveled/total time taken

                      v = s/t

                        = 40+50 km / 2 h

                        = 90 km / 2 h

                        = 45 km/h

Answer 2

$\color{lime}\boxed{ANSWER}$

$speed = \frac{distance}{time}$

$therefore \\ d = \frac{d}{40} \\ d = \frac{d}{50}$

$total \: distance = ( \frac{d}{40} + \frac{d}{50} ) = \frac{90d}{200} \\ average \: speed = 2d \times \frac{200}{90d}$

$= 4.4444$