Question

A bus moving along a straight line at 20 m/s undergoes an acceleration of 4 m/s^2 after 2 seconds,it's speed will be​

Answer 1

s = ut + 1/2 at²

s = 20×2 + ½×4×(2)²

s = 40 + ½×16

s = 40 + 8

Speed = 48 m/s²

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Answer 2

initial velocity (u)= 20m/s

final velocity (v) = ???

acceleration = 4m/s²

v = u+at

=> v = 20m/s + 4*2m/s

=> v = 28m/s

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