a bus moving along a straight line at 20m/s undergoes an acceleration of 4 m/s2.after 2 s it's speed
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Answered by
5
Explanation:
Initial speed (u) =20m/s
Acceleration (a) =4m/s^2
Time taken (t) =2s
Final speed (V) =?
As we know,
V = u+ at
=> V = 20 + 4×2
=> V = 20 + 8
=> V = 28m/s
Hence, speed after 2s is 28 m/s Ans.
Answered by
1
u=20
a=4
t=2
we have a formula v=u+at
v=20+4×2
=20+8
v=28
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