Question

A bus moving along a straight line at 20m/s undergoes an acceleration of 4m/s. After 2 second velocity is

Answer 1

Answer:

u= 20 m/s

a= 4 m/s ^2

v= u+at =20+4*2 =28m/s

Explanation:

speed will be 28 m/s.

Answer 2

Given:

A bus moving along a straight line at 20m/s undergoes an acceleration of 4m/s².

To find:

Final velocity after 2 seconds?

Calculation:

• Initial velocity (u) = 20 m/s and acceleration (a) = 4 m/s².

Applying EQUATIONS OF KINEMATICS:

$\sf \: v = u + at$

$\sf \implies v = 20 + (4 \times 2)$

$\sf \implies v = 20 + 8$

$\sf \implies v = 28 \: m {s}^{ - 1}$

So, final velocity after 2 seconds is 28 m/s.