A bus moving along a straight line at 20m/s undergoes an acceleration of 4m/s2 . calculate it's speed after 2 seconds
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We have,
u= 20m/s
a=4m/s^2
t=2sec
We know that
v=u+at
v=20+(4×2)
v=20+8=28
Hence,speed of the bus after 2 sec=28m/s
u= 20m/s
a=4m/s^2
t=2sec
We know that
v=u+at
v=20+(4×2)
v=20+8=28
Hence,speed of the bus after 2 sec=28m/s
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