A bus moving along a straight line at 20m/s undergoes an acceleration of 4m/s2 . calculate it's speed after 2 seconds
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Answers
Answered by
3
Hi friend
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Your answer
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Given that : -
A bus is moving along a straight line.
Initial velocity (u) = 20 m/s
Acceleration (a) = 4 m/s²
Time (t) = 2 Seconds
Final velocity (v) = ? [speed after 2 seconds.]
Now,
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Using formula : - v = u + at
=> v = 20 + 4 × 2
=> v = 20 + 8
=> v = 28 m/s
∴ Speed after 2 seconds is 28 m/s.
HOPE IT HELPS
---------------
Your answer
---------------------
Given that : -
A bus is moving along a straight line.
Initial velocity (u) = 20 m/s
Acceleration (a) = 4 m/s²
Time (t) = 2 Seconds
Final velocity (v) = ? [speed after 2 seconds.]
Now,
---------
Using formula : - v = u + at
=> v = 20 + 4 × 2
=> v = 20 + 8
=> v = 28 m/s
∴ Speed after 2 seconds is 28 m/s.
HOPE IT HELPS
Answered by
0
Answer:
u=20m/s
a=4m/s sq.
v=?
Now,
Using 1st eq. of motion
v=u+at
v=20+4*2
v=28m/s
Hope it will help you......
Explanation:
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