Question

a bus moving at 2m/s accelerates at 2 m s-2 for 5 seconds.how far it travels at this time​

Answer 1

Answer:

u = 2m/s

a = 2m/s^2

t = 5 s

s = ut+1/2at^2

s = 2*5+1/2*2*5

s = 10+5

s = 15 m

$...$

Answer 2

ANSWER:

• Distance traveled in 5 sec = 35 m

GIVEN:

• Initial velocity of the bus = 2m/s
• Acceleration of the bus = 2m/s²
• Time = 5 sec

TO FIND:

• Distance traveled in 5 sec.

SOLUTION:

Formula:

$\implies \: s = ut + \dfrac{1}{2} at {}^{2}$

Where:

• s = Displacement.
• u = initial velocity.
• t = time taken.
• a = acceleration.

Putting the values in the formula we get:

$\implies \: s = 2 \times 5 + \dfrac{1}{2} \times 2 \times (5) {}^{2} \\ \\ \implies \: s = 10 + 25 \\ \\ \implies \: s = 35 \: m$

• Distance traveled in 5 sec = 35 m