Question

A bus moving at a speed of 36 m/s is brought to rest in 10 s then find the acceleration and distance travelled by the bus?
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Answer 1

Answer:

We know that 1m/sec = 18/5km/sec.

speed = 36 m/sec.

now

36*18/5

648/5

rest 10sec.

distance = speed /time. = 648/5/10. = 648/2 = 324.

Answer 2

Answer:

#Red official

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u = 36 m/s

v = 0 m/s

t = 10 sec

$= {a = \frac{v - u}{t} }\\\\= a = \frac{0 - 36}{10} \\\\= a = \frac{- 36}{10} \\\\\\= a = -3.6\\\\Here\ negative\ sign \ represent \ that \ it \ is \ retardation.$

$= s = ut + \frac{1}{2}at^{2} \\\\= s = (36 \times 10) - \frac{1}{2}\times 3.6 \times 100 \\\\= s = 360 - 180\\\\= s = 180 meters$