Question

A bus moving at a speed of 36 m/s is brought to rest in 10 s then find the acceleration and distance travelled by the bus? Write on a nb or page and attach it​

Answer 1

Answer:

-3.6m/s²

Explanation:

Initial velocity of the bus(u)=36m/s

Final velocity of the bus(v)=0m/s

Time taken to stop the bus(t)=10sec

acceleration = (v-u)/t

= (v-u)/t =(0-36)/10

= (v-u)/t =(0-36)/10 = -36/10

= (v-u)/t =(0-36)/10 = -36/10 = -3.6

Hope you like this answer. If you like, please mark this answer as the brainliest and follow me.