Question

A bus moving at an average speed of 50km/hr takes 4 hrs to reach its destination. Find the distance covered by the bus.​

Answer 1

Answer:

= 2880/1000 km. = 2.88 km.

Explanation:

Speed of Ranjeet = 50 km/hr

Total distance covered by Ranjeet in 8 hrs = 50 × 8 = 400 km

Speed of Rahman = 400/5 = 80 km/hr

New speed of Ranjeet = 50 + 10 = 60 km/hr

New speed of Rahman = 80 + 20 = 100 km/hr

Time taken by Ranjeet to cover 400 km distance = 400/60 = 6 hr 40 min

Time taken by Rahman to cover 400 km distance = 400/100 = 4 hr

Required difference = 6 hr + 40 min – 4 hr = 2 hr + 40 min

Answer 2

Provided that:

• Average speed = 50 kmph
• Time taken = 4 hours

To calculate:

• The distance

Solution:

• The distance = 200 km

Using concept:

• Average speed formula

Using formula:

• ${\small{\underline{\boxed{\sf{v \: = \dfrac{s}{t}}}}}}$

Where, v denotes average speed, s denotes distance and t denotes time.

Required solution:

$:\implies \sf v \: = \dfrac{s}{t} \\ \\ :\implies \sf 50 \: = \dfrac{s}{4} \\ \\ :\implies \sf 50 \times 4 \: = s \\ \\ :\implies \sf 200 \: = s \\ \\ :\implies \sf s \: = 200 \: kilometres \\ \\ :\implies \sf Distance \: = 200 \: kilometres$