Question

A bus moving on a straight road with speo
126 kmh is brought to rest after 200 m.
acceleration of the bus
Time taken by bus to come to rest​

Answer 1

Explanation:

v=0

u= 126*5/18= 35 m/s

s = 200m

using third equations of motion

v²=u²+2as

(0)²=35²+2*a*200

0= 1225+400a

- 1225 = 400a

-1225/400=a

-3.06 m/s²=a

using first equation of motion

v=u+at

0=35+-3.06*t

-35=-3.06t

-35/-3.06=t

time = 11.43 second