Question

A bus moving with 30m/s breaks are applied and in 10 seconds it comes to rest.Acceleration produced by the car will be

Answer 1

Given :

Initial velocity of bus ,u = 30 m/s

Final velocity of bus , v = 0 m/s ( brakes are applied)

Time taken,t = 10 s

To Find :

The acceleration produced by the car

${\purple{\boxed{\large{\bold{Formula's}}}}}$

Kinematic equations for uniformly accelerated motion .

$\bf\:v=u+at$

$\bf\:s=ut+\frac{1}{2}at{}^{2}$

$\bf\:v{}^{2}=u{}^{2}+2as$

and $\bf\:s_{nth}=u+\frac{a}{2}(2n-1)$

${\underline{\sf{Answer}}}$

We have to Find the acceleration produced by the car .

From the first equation of motion,we have

v = u + at

⇒ 0 = 30+ a × 10

⇒ 0 = 30+10a

⇒ -30a = 10

⇒ a = -30/10= -3 m/s²

Therefore, The acceleration of car is -3m/s²

Answer 2

ANSWER:-

Given:-

Initial velocity (u) = 30 m/s

Final velocity (v) = 0 m/s

Time (t) = 10 s

To find:-

Accelertion (a)

Solution:-

${\star}~~~ \boxed{ \rm{a = \frac{v - u}{t} }}$

${\implies}\rm a = \frac{0 - 30}{10}$

${\implies}\rm a = \frac{ - 30}{10}$

$∴ \rm \red{a = - 3 \: m {s}^{ - 2} }$