A bus moving with 45 m/s accelerates at 3 m/s² in 8 seconds. Calculate its i. Final velocity i. Distance travelled.
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Ans : Given , Initial velocity,u = 45m/s
Final velocity,v = ?
acceleration = 3m/s²
time =8s
.. i)as we know the first eq. of motion
v=u+at
v =45 + 3×8
v=45+24
v=69M/s
ii)distance travelled by the bus
s =ut + ½at²
s=45×8 + ½×3×8×8
s=36+½×192
s=36+96
s =132m
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