Question

a bus moving with a speed of 54 km/h . on applying brakes, it stopped in 8s .calculate the acceleration and the distance travelled before stopping

Answer 1

$u = 54km \: {hr}^{ - 1} \\ \: \: \: \: \: \: = 15m {s}^{ - 1} \\ t = 8 \\ v = 0$
$using \: \frac{v - u}{t} = a \\ a = \frac{0 - 15}{8} \\ = - 1.85m {s}^{ - 2} \\ s = ut \: + \frac{1}{2} a {t}^{2} \\ s = (15)(8) - \frac{1}{2} (1.85)( {8})^{2} \\ = 120 - 59.2 \\ = 60.8m$
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