Question

a bus moving with a velocity of 100km/h and it takes 5 sec to stop after break are applied calculate the force exerted by breaks on the if its mass along with passenger is 1500kg​

Answer 1

Answer:

We are given that Initial velocity of motor car = 108 km/h ⇒ (u) = 108 × 1000 60 × 60 108×100060×60 = 30 m/s Final velocity (v) = 0 m/s Total mass of the motor car along with its passengers (m) = 1000 kg. Time is taken to stop the motor car (t) = 4 sec. The negative sign shows that the force exerted by the brakes is opposite to the direction of motion of the motor car.Read more on Sarthaks.com - https://www.sarthaks.com/778513/a-motor-car-is-moving-with-a-velocity-of-108-km-h-and-it-takes-4-sec-to-stop-after-the-brakes-one?show=778517#a778517

Answer 2

Answer:

the force required to stop the car = -8310N

Explanation:

let us first write the givern quantities ;

initial velocity ( u ) = 100km/h = 27.7m/s

final velocity ( v ) = 0m/s

force ( N ) = ?

acceleration ( a ) = ?

time ( s ) = 5 seconds

mass ( kg ) = 1500kg

Now, let us first find out the acceleration

$v = u + at\\0 = 27.7 + 5(a)\\27.7 + 5a = 0\\5a = 0 - 27.7\\5a = -27.7\\a = - 5.54m/s^2$

Now, as we know the value of acceleration we can find out the d=force exerted by the brakes

$F = ma\\F = 1500 * ( -5.54 ) \\F = -8310N$

now that's the final answer and,

thank you :-)