Question

A bus moving with a velocity of 60 km h-1 is brought to rest in 20 seconds by applying brake find acceleration

Note_ swap will be reported on the spot​

Answer 1

$\bold{Answer:-}$

$\sf\fbox\green{⟹\:Acceleration \:is\:4m/s²}$

$\bold{Step\:by\:step\:Explanation:-}$

❒ Converting Initial Velocity In m/s:-

We Have,

Initial Velocity = 60 Km/h

$= (60 \times \frac{5}{18} )second$

$\sf\fbox\red{⟹ Intial velocity = 16.66 m/s}$

Now Here We Have :-

• Initial Velocity = U = 16.66 m/s
• Finial Velocoty = v = 0 m/s
• Time = t = 20 s
• Let acceleration be = a m/s²

❒$\blue{ \underbrace{ \large \blue{ \underline{ \pink{\sf \:v=u+at}}}}}$

Applying 1st Equation of motion :

⟹ 0 = 16.66 + a × 20

⟹ -16.66 = 20a

⟹ $a\:=\:\frac{-16.66}{20}$

${ \color{magenta}{ \fcolorbox{magenta}{purple}{ { \color{white}{\fcolorbox{aqua}{black}{⟹\:a\:=\:-0.83}}}}}}$

⟹ Acceleration of bus is - 0.84 m/s²

Answer 2

Answer:

u = 60 km/h * r * 5 / 18 = 50 / (3 m/s) * e * c

v = 0

t = 20s

a=?

we know that

negative sign shows that it is a retarded motion. so its acceleration is 2.83 m/s * e * c ^ 2

... a = - 0.83 m/s * e * c ^ 2

a = - 50/60

a = - 50/3 / 20

a = v - u / t

Explanation:

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