Question

A bus moving with a velocity of 60 m/s comes to stop after applying brakes. If it takes 3 seconds to stop then calculate the acceleration it produces. pls do it ill mark u brainliest

Answer 1

Given :

• Initial Velocity (u) = 60 m/s

• Final Velocity (v) = 0 m/s

• Time (t) = 3 seconds

To Find :

• Acceleration produced (a)

Solution :

We know that, acceleration is measure of the change in velocity of an object per unit time.

★ Acceleration = Final Velocity - Initial Velocity/Time taken

→ a = $\sf\dfrac{0-60}{3}$

→ a = $\sf\cancel\dfrac{-60}{3}$

→ a = - 20 m/s²

$\therefore$ Acceleration produced is - 20 m/s²

The negative sign of acceleration means that it is retardation. So, we can also say that the bus has a retardation of + 20m/s

Answer 2

Explanation:

${\red{\underline{\underline{\bold{Given:-}}}}}$

• Initial velocity = 60m/s

• Final velocity = 0m/s

• Time taken to stop = 3 sec

${\blue{\underline{\underline{\bold{To\:Find:-}}}}}$

• The acceleration produced by the bus

${\green{\underline{\underline{\bold{Solution:-}}}}}$

According to the first equation of motion :-

$\bf v = u \: \: + \: at$

Here:-

• v = final velocity

• u = initial velocity

• a = acceleration

• t = time

Substituting the values:-

We get

$\implies \bf v = u \: \: + \: at$

$\implies\bf 0 \: = \: 60 \: \: + \: a(3)$

$\implies\bf \: 60 \: \: + \: 3a \: = \: 0$

$\implies\bf 3a \: = \: - 60$

$\implies\bf a \: = \: \dfrac{ - 60}{ \: \: 3}$

$\implies\bf a \: = \: { - 20}$

$\boxed{ \bf Acceleration \: \: = \: - 20m/ {s}^{2} }$

Note:-

Here, the negative sign indicates negative acceleration (or) retardation