Question

A bus moving with a velocity of 60km h-1 is brought to rest in 20second by applying break.find the acceleration

Answer 1

We know that :-

a = v - u / t

u = 60 km / h

= 60 * 10/36

= 100 / 6 m/s

Therefore,

a = 0 - 100/6 ÷ 20

a = - 100 / 6*20

a = - 5/6 m/s^2

a = - 0.833 m/s^2

Note : negative sign indicates acceleration in opposite direction.