A bus moving with a velocity of 60km /h is brought to rest in 20 seconds by applying brakes .find the acceleration.
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Answer:
Acceleration = - 0.85 m/ (Deceleration)
Explanation:
u = 60 Km/h = 60 x 5/18 = 16.66 m/s (approx , 17 m/s)
t = 20 s
v = 0 m/s (bus comes to rest)
First law of motion : v = u + at
a = v - u / t
= - 17 /20 = - 0.85 m/
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A bus moving with a velocity of 60 km/h is brought to rest in 20 seconds by applying brake find acceleration ?
- Initial Velocity ( u ) = 60 Km/h
- Final Velocity ( v ) = 0 m/s ( At rest )
- Time taken ( t ) = 20 s
- Acceleration of bus ( a ) .
- Acceleration
Acceleration is the rate at which velocity changes with time . Acceleration can be negative , positive or zero . Negative acceleration is called retardation .
- Initial Velocity
Initial velocity is the velocity of the object before the effect of acceleration .
- Final Velocity
Final velocity is the velocity of the object after the effect of acceleration .
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