A bus moving with the velocity of 60km/hr brought to rest in20s by applying brakes. Find its retardation
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Given :
Initial velocity of the bus, u = 60 km/h
Final velocity of the bus, v = 0m/s
Time taken, t = 20 sec
To Find :
retardation of the bus.
Solution :
First of all we have to convert km/hr to m/s
1 km/hr = 5/18m/s
60km/hr = 60 × 5/18 = 16.66 m/s
as we are provided with initial Velocity, final velocity and time we can use 1st equation of motion .i.e.,
➠ v = u + at
by, substituting all the given values,
➠ 0 = 16.66 + (a)(20)
➠ -16.66 = 20a
➠ -16.66/20 = a
➠ a = - 0.83 m/s²
thus, the retardation of bus is - 0.83 m/s².
Remember !
If the speed is decreasing with time then accerlation is negative. The negative accerlation is called retardation.
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