A bus moving with the velocity of 60kmh-1is brought to rest in 20s by applies breaksv.find its accleartion
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Answered by
1
Answer:
Explanation:
Acceleration = final velocity -intial velocity ÷time
A =0-60÷20
A=-30m/s²
Answered by
0
Answer: -1/6 m/s^2
Explanation: v = 0 m/s
u = 60 km/hr
=60*5/18
= 10/3 m/s
t = 20 seconds
a=v-u/t
=(0 - 10/3) /20
=-10/3 /20
=-10/3*1/20
=-1/6 m/s^2
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