A bus moving with velocity of 72km/hr has acceleration 0.5m/s^2. How long will it take to gain the velocity of 27m/s?
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Using first equation of motion, we know,
v = u + at
Here, u = 72 km/h
Convert it into m/s by multiplying 5/18,
So, we get u = 72 ×5/18 m/s which is 20 m/s
a = 0.5 m/s^2
v = 27 m/s
A/Q,
v = u + at
27 = 20 + 0.5t
27 - 20 = 0.5t
7 = 0.5t
t = 7 ÷ 0.5
t = 14
Hence, it will take 14 seconds for the bus to attain a velocity of 27m/s.
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