A bus of mass 10,000 kg is moving with a velocity of 90km/h. Find the work done to stop the bus ..
Answers
Answered by
17
m = 2000 kg
u = 0
v = 90 km/hr = 25 m/s
Work done = change in K.E
= 1/2 m(v ² - u²)
= 1/2 × 2000× 25²
= 625000 J
u = 0
v = 90 km/hr = 25 m/s
Work done = change in K.E
= 1/2 m(v ² - u²)
= 1/2 × 2000× 25²
= 625000 J
Answered by
17
Answer:
answer is below
Explanation:
m=10000 kg
v=90 km/h=90X5/18
v=25 meter per second
w= kinetic energy = 1/2 mv 2
w= 1/2 X 10000 X 25 X25
w= 125000 X 25
wo = 312500 joules
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