Question

A bus of mass 10*4 kg moves on a rough road with a constant acceleration of 2m/s the friction of the road is 9percent

Answer 1

Answer:

10

Explanation:

multiple do get anwer

Answer 2

The power of the engine = 600 kW

Given:

Mass of the bus = 10⁴ Kg

Acceleration of the bus = 2 m/s²

The friction of the road = 9% of its weight

The friction of air = 1% of its weight

Speed of the bus = 72 Km/hr

To find:

The power of the engine.

Solution:

• Power may be defined as the amount of energy which is transferred per unit of time.
• The SI unit of power is Kgm²/s³

• Force exerted on the bus is the sum of the force due to its acceleration and due to the frictional force of the road and the frictional force of the air.

F (exerted) = m × a + f (road) + f (air)

F (exerted) = 10⁴ × 2 + 10⁴ × 10 × 9/100 + 10⁴ × 10 × 1/100

F (exerted) = 3 × 10⁴ N

The velocity of the bus = 72 Km/hr

V = 20 m/sec

Therefore,

Power = F (exerted) × velocity

Power = 3 × 10⁴ × 20 W

Power = 600 kW

The power of the engine = 600 kW

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