Question

a bus of mass 2000 kg starts from rest and rolls down a hill .If it travels a distance of 100m in 10seconds .Calculate (1) acceleration of bus and (2) the force acting on the bus​

Answer 1

Answer:

Explanation:

use

s=$\frac{v+u}{2}$×t

to find the final velocity

s=distance=100m

v = final velocity=?

u= initial velocity= 0

t= time= 10s

after substituting you get 20m/s for the final velocity

then use v=u+at to find the acceleration,

therefore we get 2ms^-2 for the acceleration

then to find force

use f=ma

f=force=?

m=mass=2000kg

a = acceleration=2ms^-2

then you get 4000N for force

Answer 2

Given : A bus of mass 2000kg starts from rest and come down a hill with a constant acceleration .

It travels a distance of 100m in 10 s .

To Find :  acceleration of the bus

force acting on the bus​

Solution:

u = 0   ( rest)

a = ?

t = 10 s

S = 100 m

S = ut + (1/2)at²

=> 100 = 0 + (1/2)a (10)²

=> 100 =  50a

=> a = 2

Hence acceleration is  2 m/s²

F = ma

m = 2000 kg

a =  2  m/s²

F = 2000 *  2

=> F = 4000 N

Force is 4000 N

1) acceleration of bus  = 2 m/s²

(2) the force acting on the bus​ = 4000 N

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