Question

A bus of mass 5000 kg starts from a rest and rolls down a hill.If it travels a distance of 200 m in 10 seconds.Find

(a) acceleration of a bus
(b) The force acting on the bus

Answer 1

Initial velocity (u) = 0 m/sec
Time (t) = 10 sec
Distance (S) = 200 m

Formula used :
S = ut + 1/2 at²
200 = 0×t + 1/2 a×(10)²
200 = 1/2 a×100
100×a = 400
a = 400/100
a = 4 m/sec²

Force = Mass × Acceleration
         = 5000 × 4
          = 20000 Newton.

Answer 2

Answer:

ANSWER = 20,000 N

Explanation:

Given that

Mass = 5000kg

Initial velocity =0

Distance= 200m

Time= 10 sec

Then find force acting on it.

We know that

F=ma.

From 1st law of motion

S=ut +1/2at2

200=0+1/2a×100

400=100a

a=4m/s2

Now from equation (i)

F= 5000 × 4

F= 20000 N