Question

A bus running at a speed of 12 km/h is stopped in 2 secs by applying brakes, the retardation produced is- *
1 point 1.67 m/s²
-1.67 m/s²
0.67 m/s²
-0.67 m/s²

Answer 1

Answer:

given

initial velocity = 12km/h

= 12*5/18 m/s

= 10/3 m/s

final velocity = 0

time taken = 2 s

acceleration = v-u/t

0 - 10/3/2

= - 1.67m/s^2

retardation = 1.67 m/s^2