A bus running at a speed of 12 km/h is stopped in 2 secs by applying brakes, the retardation produced is- *
1 point 1.67 m/s²
-1.67 m/s²
0.67 m/s²
-0.67 m/s²
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Answer:
given
initial velocity = 12km/h
= 12*5/18 m/s
= 10/3 m/s
final velocity = 0
time taken = 2 s
acceleration = v-u/t
0 - 10/3/2
= - 1.67m/s^2
retardation = 1.67 m/s^2
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