Question

a bus running at a speed of 18 km per hour is stop add in 2.5 seconds by applying brake.calculate the retardation produced​

Answer 1

$\huge{\mathfrak{Answer:-}}$

Retardation is nothing but acceleration in the opposite direction.

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Given:-

u = 18km/h = 18×1000/3600 = 5 m/s

t = 2.5s

v = 0

(v = 0 because the brakes are applied,Hence, the bus comes to a rest)

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Formula used:-

$\boxed{v=u+at}$

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Solution:-

0 = 5 + a(2.5)

-5 = a × 2.5

a = $\frac{-5}{2.5}$

a = -2

Hence, the retardation is

$\boxed{\huge{\star{\bf{2ms^{-2}}}}}$

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Cheers,

N ❤✌