Question

a bus running at a speed of 18 km per hour is stopped in 2.5 seconds by applying brakes calculate retardation

Answer 1

u=18×5÷18m/s=5m/s
v=0
t=2.5sec
a=(v-u)/t
=(0-5)/2.5
=-5/2.5
=-2m/s^2

Answer 2

v=18km/hr=18000/3600=5m/s
u=0m/s
t=2.5s
by using formula:-
v=u+at
5=0+(-a)2.5......…....retardation taken as '-a'
-2.5a=5
-a=5/2.5
-a=2m/s^2

therefore retardation is 2m/s^2

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