Question

a bus running at a speed of 18km/h is stopped in
2.5seconds by applying breaker. calculate the retardation produced

Answer 1

U=18 km/h

$= 18\times \frac{1000}{3600}$
=5m/S
v=0m/s
t= 2.5s

as we know retardation is negative accleration
acceleration =change in velocity
$a = \frac{v - u}{t}$
$a = \frac{0 - 5}{2.5}$
$a = \frac{ - 5}{2.5}$
a=-2 m/s^2




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Answer 2

what are the two length which are bigger than metre