Question

a bus running at a speed of 18km/hr is stopped in 5sec by applying breaks. calculate the retardation produced.​

Answer 1

Explanation:

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Answer 2

Answer:

Initial velocity, u=18 km/h

u=18×

3600

1000

=

3600

18000

m/s=5m/s

Final velocity, v=0 m/s

Time, t=2.5 sec

Acceleration, a=?

Using, v=u+at

a=

t

v−u

=

2.5

0.5

=−2m/s

2

So, retardation is 2m/s

2

..