Physics, asked by ankitsinghabd1852, 10 months ago

A bus running at speed of 18 km /h is stopped in 2.5 seconds by applying brakes . Calculate the retardation produced

Answers

Answered by Anonymous
4

Answer:

Explanation:

initial velocity = 18 km/h = 18×5/18 m/sec

= 5 m/sec

[ km/h = 5/18 m/sec ]

final velocity = zero

acceleration = change in velocity/time

= ( final velocity - intial velocity)/time

= ( 0 - 5)/2.5 = -2 m/s²

so, retardation = 2m/s²

Answered by mankaovi1025
1

Answer:

-2 m/sec^2

Explanation:

Intial velocity = 18 km/h

To convert km/h into m/sec we have to divide it by 5/18.

Therefore,

18 km/h = 18*5/18

= 5 m/sec

Final velocity = 0 (Bcoz the bus stopped)

Time Taken = 2.5 sec

Acceleration = Change in velocity/Time

= Final velocity - Initial Velocity / Time

= 0-5/2.5

= -50/25 = -2 m/sec^2 Ans.

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