Question

A bus running at speed of 18km /h is stopped in 2.5 second by applying break.calculate the retardation produced.​

Answer 1

-2m/s minus two metre per second

Answer 2

Retardation = (u-v)/t = [(-18000/3600)/2.5] m/s^2

$= \frac{ - 50}{25} = - 2m {s}^{ - 2}$

The negative sign shows that the body has retarded.

HOPE THIS COULD HELP!!!