Question

a bus running with a velocity of 72 kilometre per hour on seeing a boy and the road 65 meter ahead the bus stopped calculate the distance travelled by the bus and discuss whether the accident took place or not (the bus again retardation of 5 metre per second square2


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Answer 1

Answer:

distance travelled by the bus is 40 m and hence the accident is avoided as the boy is standing 65m away .

Explanation:

firstly we will find the time taken by the bus to stop and then we can find the distance travelled by the bus afer the breaks are applied

so,

v = om/s

u = 72 × 5/ 18        ( converting it into m/s by multiplying it with 5/18)

   = 20m/s

a = - 5m/s^2          ( -ve sign as accerlation is _ve of the retardation )

by applying identity  v = u +at

0 = 20 - 5 t

t = 4s

now   s = ut + 1/2 at^2

s = 20 × 4 + 1/2× ( -5 ) × 4×4

 = 80 - 40

 = 40m