Question

A bus runs at 40 km/h to reach its destination but arrives 11 min late. If it runs at
50 km/h, it will be 5 min late. Find the correct time in which the bus will not be late in
reaching its destination​

Answer 1

Answer:

❀ʀᴇǫᴜɪʀᴇᴅ ᴀɴsᴡᴇʀ:

Let the correct time for the train to complete the journey is x minuets

Then train cover distance in x+11 minuets at speed 40 km\hr = $\frac{40(x + 11)}{60} km$

Then train cover distance in x+5 minuets at speed 50 km\hr = $\frac{50(x + 5)}{60} km$

Both are same then $\frac{40(x + 11)}{60} = \frac{50(x + 5}{60}$

∴40x+440=50x+250

∴−10x=−190

∴x=19 minutes

hence the answer is x= 19 minutes

$\sf\blue{hope \: this \: helps \: you!! \: }$

Answer 2

Step-by-step explanation:

❀Required ANSWER

Let the correct time for the train to complete the journey is x minuets

Then train cover distance in x+11 minuets at speed 40 km\hr = \frac{40(x + 11)}{60} km6040(x+11)km

Then train cover distance in x+5 minuets at speed 50 km\hr = \frac{50(x + 5)}{60} km6050(x+5)km

Both are same then \frac{40(x + 11)}{60} = \frac{50(x + 5}{60}6040(x+11)=6050(x+5

∴40x+440=50x+250

∴−10x=−190

∴x=19 minutes

hence the answer is x= 19 minutes