A bus runs at 40 km/h to reach its destination but arrives 11 min late. If it runs at
50 km/h, it will be 5 min late. Find the correct time in which the bus will not be late in
reaching its destination
Answers
Answer:
❀ʀᴇǫᴜɪʀᴇᴅ ᴀɴsᴡᴇʀ:
Let the correct time for the train to complete the journey is x minuets
Then train cover distance in x+11 minuets at speed 40 km\hr =
Then train cover distance in x+5 minuets at speed 50 km\hr =
Both are same then
∴40x+440=50x+250
∴−10x=−190
∴x=19 minutes
hence the answer is x= 19 minutes
Answer:
In 19 minutes, the bus will not be late in reaching its destination.
Step-by-step explanation:
This question can be solve by 2 methods.
Given -
A bus runs at 40 km per hour to reach its destination.
The bus arrives 11 mins late.
It runs at 50 km per hour it will be 5 minute late.
To Find
The time in which the bus will not be late in reaching its destination.
Solution 1 -
Consider the -
Time as - t.
It implies,
Increase in speed by 25% will decrease of 1/5th in time if distance is constant.
So,
We get the normal time as 30 minutes. But it is given that the bus arrives 11 mins late.
So,
∴ The answer is 19 Minutes.
Solution 2 -
Find the Ratio of the speeds & Time.
So,
Ratio of speeds = 40 : 50 = 4 : 5
Now,
If distance is constant then, Time is inversely proportional to Speed.
So,
Time Ratio = 5 : 4
Time saved =
⇒ 30 minutes.
⇒ 30 - 11 = 19 minutes.
∴ The answer is 19 Minutes.