A bus slows down from 43.5 km/h to 34.5 km/h in a school zone. Determine the magnitude of the vehicle's acceleration if it took 12.5 s to slow down.
Write your answer to two decimal places in m/s2.
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Answer:
•initial velocity= 43.5 km/h
(in m/s)= 43.5 × 5/18 = 12.08 m/s (u)
• Final velocity= 34.5 km/h
(in m/s) = 9.58 m/s (v)
•Time = 12.5 s (t)
• Acceleration (a)
Now substituting the values in above formula
Negative sign shows Negative a acceleration or Retardation
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