Question

A bus standing from rest moves with a uniform acceleration of 0.1 ms-2 for 12 s. Find (a) the speed acquired (b) the distance travelled.

Answer 1

Answer:

Explanation:

see the attached file

Answer 2

$\underline\text{Here\:\:they\:\:have\:\:given:-}$

Initial velocity (u) = 0m/s

Acceleration (a) = 0.1ms^(2)

Time (t) = 2 minutes = 120 seconds

• The speed acquired :-

$\underline\text{We\:\:know:-}$

$\begin{gathered}\tt \: v = u + at \\ \tt \: v = 0 + 0.1 \times 120 \\ \\ \tt \: v = 12 \: {ms}^{ - 1}\end{gathered}$

• The distance travelled:-

$\underline\text{We\:\:know:-}$

s = ut + ½at^{2}

➝0×120 + 1/2×0.1×120^2

➝1/2 ×0.1 ×14400 m= 720 m

$\underline\text{Thus\:\:bus\:\:will\:\:travel\:\:of\:\:720m\:\:in\:\:2\:\: minutes:-}$