A bus start from imphal for chassad travelling at the rate of 20km/hr. After 1half hrs,a car starts from imphal and travelling at the rate of 30km/hr reaches chassad 22 minutes ahead of the bus. Find the distance from imphal to chassad?
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we will use here second equation of motion
s=ut+1/2×at^2
and for that we need acceleration so we use 1st equation of motion
v=u+at
20=30+a×82
82a=30-20
a=82/10
a=8.2
so now we can find
s=30×82+1/2×8.2×82^2
s=30028.4
s=ut+1/2×at^2
and for that we need acceleration so we use 1st equation of motion
v=u+at
20=30+a×82
82a=30-20
a=82/10
a=8.2
so now we can find
s=30×82+1/2×8.2×82^2
s=30028.4
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