Physics, asked by sumankumari048sths, 1 month ago

a bus start from rest an moves with uniform motion of 1 m/s² for 2 minutes. calculate-
1) the speed accurate
2) the distance travel by bus​

Answers

Answered by geetasahani
0

Answer:

A bus starting from rest moves with a uniform acceleration of 0.1 m s-2 for 2 minutes. Find (a)the speed acquired, (b) the distance travelled. Thus, the bus will acquire a speed of 120 m/s after 2 minute with the given acceleration. Thus, bus will travel a distance of 720 m in the given time of 2 minute.

Explanation:

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Answered by anushkap2239
0

Answer:

Answer given below

Explanation:

travelled.

Given

The bus starting from rest moves with a uniform acceleration of 0.1 m s-2 for 2 minutes

Find out

Acceleration and distance travelled

Solution

(a) Acceleration

The bus starts from rest.

Therefore, initial velocity (u) = 0 m/s

Acceleration (a) = 0.1 m.s-2

Time = 2 minutes = 120 s

Acceleration is given by the equation a=(v-u)/t

Therefore, terminal velocity (v) = (at)+u

= (0.1 m.s-2 * 120s) + 0 m.s-1

= 12m.s-1 + 0 m.s-1

Therefore, terminal velocity (v) = 12m/s

(b) As per the third motion equation,

Since a = 0.1 m.s-2, v = 12 m.s-1, u = 0 m.s-1, and t = 120s, the following value for s (distance) can be obtained.

Distance, s =(v2 – u2)/2a

=(122 – 02)/2(0.1)

Therefore, s = 720m.

The speed acquired is 12m.s-1 and the total distance traveled is 720m.

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