a bus start from rest and move down a hill with contant acceleration the bus travel a distance of 200 m in 10 second.if the mass of the bus is 15 metric tomme, what will be the acceleration and the force acting on it 1 metric tomme=1000kg
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actually
u = S/t = 200/10 = 20 m/sec
hence acceleration a = v - u / t let the bus stops due to continuous force acting on it......so final velocity V = 0
F = ma = 1000 × v - u / t....
= 1000 × ( 0 - 20 / 10 )
= 1000 × (-2)
F = - 2000 N
negative sign tells that force is opposing the motion of body......
hence F = 2000 N and a = 2 m/sec2
u = S/t = 200/10 = 20 m/sec
hence acceleration a = v - u / t let the bus stops due to continuous force acting on it......so final velocity V = 0
F = ma = 1000 × v - u / t....
= 1000 × ( 0 - 20 / 10 )
= 1000 × (-2)
F = - 2000 N
negative sign tells that force is opposing the motion of body......
hence F = 2000 N and a = 2 m/sec2
guuda:
thnx
is it correct ?
yes
can u please mark it as brainliest ?? please
?.
thnx guuda dear ( Aditya )
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