Question

a bus start from rest under an acceleration of 4 m / s^2 calculate velocity and distance covered after 10 second​

Answer 1

Solution:-

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Given:

u = 0

a = 4m/s²

t = 10 secs

s = ?

v = ?

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1) To Find v, We will use the formula:

v = u + at

v = 0 + 4 * 10

v = 40 m/s

Therefore Velocity after 10 seconds is 40 m/s

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2) To Find Distance, We will use the formula

s = ut + 1/2 at²

s = 0 * 10 + 1/2 * 4 * 10 * 10

s = 0 + 1 * 2 * 10 * 10

s = 0 + 200

s = 200m

Therefore, Distance covered is 200m.

Answer 2

Answer:

Explanation:

OK.

Suppose I draw a tringle shape.

The 90 degree prt of the triangle is to the bottom right.

The one point of the triangle is the bottom left.

Now you haave the chart of the speed from zero to 1 second.

The Upper right point of the triangle is the 4 mark on the scale.

So waht would be the area under the triangle?

of the 16 prts tht could be covered by the squares from zero to 4, then the triangle would cover half.

50% of 4 would be 2.

So at the end of 1 second, the bus would be trvelling 2 meters per second.