Question

a bus started moving from A which velocity 36 km per hour it remains in uniform motion for 1 minutes then it started getting speed at the rate of 1 minute per second square and it reach the place B at 2 minutes after it started its motion against travel with constant speed for the next one minute and comes to rest in next 35 seconds due to uniformly retardation then find the speed achieved when it reaches to be second the retardation of the bus ​

Answer 1

Answer:

u=18km/h

= 5m/s

a = -1m/s

v = 0m/s (comes to rest )

So,

v =u +at

0=5+(-1)×t

0=5-t

t= 5 seconds

Now,

Distance travelled (s)

2as =v^2 - u ^2

2 (-1) s = (0)^2 -(5)^2

-2 s = -25

s =-25/-2

s = 12.5m

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Explanation: