A bus starting form rest moves with a uniform acceleration of 0.1 m/s2 for 2 minutes. Find (a) the speed acquired, (b) the distance travelled.
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Answered by
11
Initial velocity(u)= 0m/s
Acceleration(a)= 0.1m/s^-2
Time= 2 mins=60*2=120 secs
Final velocity=?
v=u+at
v=0+(0.1)120
v=0+12
v=12m/s
i.e.
Final Velocity= 12m/s
Distance(s)=v(v)-u(u)=2a
s=144-0=2(0.1)
s=144=0.2
s=1440=2
s=720m
Therefore,
(a)=12m/s
(b)=720m
Acceleration(a)= 0.1m/s^-2
Time= 2 mins=60*2=120 secs
Final velocity=?
v=u+at
v=0+(0.1)120
v=0+12
v=12m/s
i.e.
Final Velocity= 12m/s
Distance(s)=v(v)-u(u)=2a
s=144-0=2(0.1)
s=144=0.2
s=1440=2
s=720m
Therefore,
(a)=12m/s
(b)=720m
Answered by
4
v=u+at
v=0+0.1*120
v=12m/s
s=ut+½at²
s=0*120+½*0.1*120²
s=720
v=0+0.1*120
v=12m/s
s=ut+½at²
s=0*120+½*0.1*120²
s=720
karanjot2005:
THANKS
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