Question

A bus starting from a bus stop and moving with uniform acceleration attain a speed of40km/hr in 10 minutes.find it's acceleration​

Answer 1

$\bigstar$ Answer $\bigstar$

$\checkmark$ Given:

A bus starting from a bus stop and moving with uniform acceleration attain a speed of 40 km/hr in 10 minutes.

$\checkmark$ To Find:

Acceleration (a)

$\checkmark$ Solution:

$\star$ Equation of Motion

$\green{\implies \boxed{\rm v=u+at}}$

Here,

• u = Initial Velocity
• v = Final Velocity
• a = Acceleration
• t = Time

Given that,

$\star$ u = 0 m/s [starts from rest]

v = 40 km/hr

Converting km/hr to m/s

[ divide the speed value by 3.6 ]

Hence,

$\star$ v = 11.11 m/s

t = 10 min = 10 x 60 sec

$\star$ t = 600 seconds

According to the Question,

We are asked to find the Acceleration​ (a)

Hence,

• u = 0 m/s
• v = 11.11 m/s
• t = 600 sec

Substituting the values,

We get,

$\blue{\rm \implies 11.11=0+a(600)}$

$\green{\rm \implies 11.11=a(600)}$

$\red{\rm \implies a(600)=11.11}$

$\orange{\rm \implies a=\dfrac{11.11}{600} \ m/s^{2}}$

$\pink{\rm \implies a=0.0185 \ m/s^{2}}$

Hence,

$\checkmark$ Acceleration (a) = 0.0185 m/s²

Answer 2

Answer:

Explanation:

Solution,

Here, we have

Initial velocity, u = 0 (As train starts from rest)

Final velocity, v = 40 km/h = 40 × 5/18 = 100/9 = 11.11 m/s

Time taken, t = 1 min = 10 × 60 = 600 seconds

To Find,

Acceleration, a = ??

According to the 1st equation of motion,

We know that,

v = u + at

So, putting all the values, we get

v = u + at

⇒ 11.11 = 0 + a × 600

⇒ a = 11.11 - 0/600

⇒ a = 11.11/600

⇒ a = 0.0185 m/s²

Hence, the acceleration by train is 0.0185 m/s².

Some Important term,

Retardation - When the final speed of a body is less than its initial speed, the body is said to be retardation. Retardation can also be expressed as acceleration with a minus (-) sign.